# SOLUTION: Sarsh is designing a rectangular garden in her back yard. The length of the garden is to be three feet less than twice its width. if the perimeter of the garden is sixty feet, what

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 Question 158232: Sarsh is designing a rectangular garden in her back yard. The length of the garden is to be three feet less than twice its width. if the perimeter of the garden is sixty feet, what are the width and length of her gardenFound 2 solutions by checkley77, nerdybill:Answer by checkley77(12569)   (Show Source): You can put this solution on YOUR website!LENGTH=2W-3 WIDTH=W 2(2W-3)+2W=60 4W-6+2W=60 6W=60+6 6W=66 W=66/6 W=11 FEET. L=2*11-3 L=22-3 L=19 FEET PROOF: 2*19+2*11=60 38+22=60 60=60 Answer by nerdybill(6948)   (Show Source): You can put this solution on YOUR website! Sarsh is designing a rectangular garden in her back yard. The length of the garden is to be three feet less than twice its width. if the perimeter of the garden is sixty feet, what are the width and length of her garden . Let w = width of garden then from: "The length of the garden is to be three feet less than twice its width." we have 2w-3 = length of garden . Perimeter for any rectangle is 2(length + width) . The problem also gave us the perimeter as 60 feet, therefore: 60 = 2(w + (2w-3)) 60 = 2(w + 2w - 3) 60 = 2(3w - 3) 60 = 6w - 6 66 = 6w 11 feet = w (width of garden) . For the length: 2w-3 = 2(11)-3 = 22-3 = 19 feet (length of garden)