SOLUTION: a father is older than his son by 32 years.6 years ago the father was 17 times as old as his son.how old are they now?
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Question 157676: a father is older than his son by 32 years.6 years ago the father was 17 times as old as his son.how old are they now?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
a father is older than his son by 32 years.6 years ago the father was 17 times as old as his son.how old are they now?
.
Let x = son's current age
then from: "a father is older than his son by 32 years"
x+32 = father's current age
.
To derive our equation, we use "6 years ago the father was 17 times as old as his son"
(x+32)-6 = 17(x-6)
x+32-6 = 17x-102
x+26 = 17x-102
x+128 = 17x
128 = 16x
8 years = x (son's age)
.
Father's age:
x+32 = 8+32 = 40 years
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