SOLUTION: The sum of two numbers is 10.Three times one of them is more than four times the second by 2. Find the numbers.
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Question 157467: The sum of two numbers is 10.Three times one of them is more than four times the second by 2. Find the numbers.
Found 2 solutions by nerdybill, jojo14344:
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
The sum of two numbers is 10.Three times one of them is more than four times the second by 2. Find the numbers.
.
Let x = one number
and y = second number
.
Since we have two unknowns, we'll need two equations.
.
From: "The sum of two numbers is 10" we get:
x + y = 10 (equation 1)
.
From: "Three times one of them is more than four times the second by 2" we get:
3x = 4y+2 (equation 2)
.
Solve equation 1 for y:
x + y = 10
y = 10 - x
.
Plug the above into equation 2 and solve for x:
3x = 4y+2
3x = 4(10 - x)+2
3x = 40 - 4x + 2
7x = 40 + 2
7x = 42
x = 6
.
Plug the above into equation 1 and solve for y:
x + y = 10
6 + y = 10
y = 4
.
Solution: the two numbers are 4 and 6
Answer by jojo14344(1513) (Show Source): You can put this solution on YOUR website!
Let = 1st no.
= 2nd no.
1st condition: ------------------------> eqn 1
2nd condition: -----------------------> eqn 2
.
In 2nd condition, 3 times one of them is more than 4 times the other by 2, right?
.
In eqn 1 we get, ----------------------> eqn 3, substitute in eqn 2
---->
------------> 2nd no.
Go back eqn 3: -------------> 1st no.
It satisfy the 1st condition:
Thank you,
Jojo
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