SOLUTION: Find two numbers whose sum is 147 and one is 4 greather than three eigths of the other.

Question 157400: Find two numbers whose sum is 147 and one is 4 greather than three eigths of the other.
Answer by gonzo(654) (Show Source): You can put this solution on YOUR website!
let x = one of the numbers.
let y be the other number.
equation for the sum of the numbers being equal to 147 is
x+y=147
one of the number is 4 greater than 3/8 times the other number.
in equation form, this becomes

substituting for x in the original equation to eliminate one of the unknowns we get
x+y=147
becomes (3/8*y+4)+y=147
multiplying both sides of the equation by 8 to get rid of the fraction and the equation becomes
(8*3/8*y) + (8*4) + (8*y) = 8*147
becomes
(3*y) + 32 + (8*y) = 1176
becomes
11*y = 1144
becomes
y = 104
going back to the original equation of x+y = 147, we get x + 104 = 147 which becomes x = 147 - 104 which becomes x = 43.
answer is x = 43 and y = 104.
substituting in the original equation of x+y=147, we get 104+43=147 which becomes 147=147 which confirms the values for x and y are correct for the original equation.
substituting in the x = 3/8*y + 4 equation, we get 43 = ((3*104)/8)+4 which becomes (312/8) + 4 which becomes 39 + 4 = 43.
43 = 43 confirms x and y have the correct values.
answer is:
x = 43
y = 104

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