SOLUTION: Help! Adult tickets for a show cost $5.50 while children's tickets cost $2.50.If there were twice as many adults as children and the total receipts for the show were $1026 how man

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Help! Adult tickets for a show cost $5.50 while children's tickets cost $2.50.If there were twice as many adults as children and the total receipts for the show were $1026 how man      Log On

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Question 156806: Help!
Adult tickets for a show cost $5.50 while children's tickets cost $2.50.If there were twice as many adults as children and the total receipts for the show were $1026 how many adults were at the show?
Answer by nerdybill(5412) About Me  (Show Source):
You can put this solution on YOUR website!
Adult tickets for a show cost $5.50 while children's tickets cost $2.50.If there were twice as many adults as children and the total receipts for the show were $1026 how many adults were at the show?
.
Let C = number of children
then from:"there were twice as many adults as children"
2C = number of adults
.
5.50(2C) + 2.50C = 1026
5.50(2C) + 2.50C = 1026
11C + 2.50C = 1026
13.50C = 1026
C = 1026/13.50
C = 76
.
To calculate adult tickets:
adult tickets = 2C = 2(76) = 152 (adults at show)