# SOLUTION: Walt made an extra \$9000 last year from a part-time job. He invested part of the money at 9% and the rest at 8%. He made a total of \$770 in interest. How much was invested at 8%?

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Walt made an extra \$9000 last year from a part-time job. He invested part of the money at 9% and the rest at 8%. He made a total of \$770 in interest. How much was invested at 8%?       Log On

 Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo . Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Linear Solvers Practice Answers archive Word Problems Lessons In depth

 Click here to see ALL problems on Linear Equations And Systems Word Problems Question 149209: Walt made an extra \$9000 last year from a part-time job. He invested part of the money at 9% and the rest at 8%. He made a total of \$770 in interest. How much was invested at 8%? Please show all work....Answer by mangopeeler07(462)   (Show Source): You can put this solution on YOUR website!x=9% money y=8% money coefficient=percent x+y=9000----------------------because there was \$9000 extra 9x+8y=77000-------------------because 9% x + 8% y= 77000% (or 770) Solve for x in the first equation x=9000-y Plug that in 9(9000-y)+8y=77000 Distribute the 9 to the parentheses 81000-9y+8y=77000 Combine like terms 81000-y=77000 Subtract 81000 from both sides -y=-4000 Divide by -1 y=4000 y=8% money money invested at 8%: \$4000