SOLUTION: How do you do this problem? "Phone and water bills together cost a company $790 for December. If the phone cost four times as much as the water, how much was each utility? How do y
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Question 145947This question is from textbook Algebra For college students
: How do you do this problem? "Phone and water bills together cost a company $790 for December. If the phone cost four times as much as the water, how much was each utility? How do you make it an algebraic expression that I can work through? Please help! Thank you!
This question is from textbook Algebra For college students
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Let x = phone cost
Let y = water cost
:
Write an equation for each statement:
"Phone and water bills together cost a company $790 for December."
x + y = 790
:
" If the phone cost four times as much as the water,"
x = 4y
:
how much was each utility?
:
Using the 1st equation; x + y = 790, substitute 4y for x
4y + y = 790
5y = 790
y =
y = $158 is the water bill
:
Using x = 4y, substitute 158 for y
x = 4(158)
x = $632 is the phone bill
:
:
Check 158 + 632 = 790; confirms our solutions
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