You can
put this solution on YOUR website!Suppose:
x is the first number
y is the second number
z is the third number
We can construct mathematic model from the problem:
x + y + z = 6
z=x+y
x=z+1
Look the first equation and the second equation:
x+y+z=6
(x+y)+z=6
z+z=6
2z=6
z=3
Substitute z=3 to x = z+1
x = z+1
x = 3+1
x=4
Substitute x=4 and z=3 to z=x+y
z=x+y
3=4+y
3-4=y
y=-1
Thus, the first number is 4, the second number is -1, and the third number is 3
OK
You can
put this solution on YOUR website!let x = third number
y = first number
z = second number
We know x+y+z=6
also x = y+z (1).
and y = x+1 (2).
plug y back into equation (1) to get x = (x+1) + z.
Now subtract x from both sides of this equation to get
0=1+z.
Now subtract 1 from both sides to get
-1=z.
Now we know x=y+(-1), x+y+(-1)=6.
plug x into this equation to get
(y+(-1)) + y + (-1) = 6
solve for y.
we have,
y-1+y-1=6
2y-2=6
add 2 to both sides to get
2y=8
now divide by 2 to get
y=4
Now that we know z and y we can use equation (1) to find x.
x=4+(-1)= 3.
Hope this helps
(