SOLUTION: I have to set up equations and solve them. I have a hard time translating the problem though. I can do the math work. One number is 7 less than a second number. Twice the seco

Question 138194: I have to set up equations and solve them. I have a hard time translating the problem though. I can do the math work.
One number is 7 less than a second number. Twice the second number is 50 more than 5 times the first. Find the two numbers.

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
One number is 7 less than a second number. Twice the second number is 50 more than 5 times the first. Find the two numbers.
------------
Let 1st be "a"; Let 2nd be "b"
EQUATIONS:
a = b-7
2b = 5a+50
---------------
Rearrange to get:
a - b = -7
5a - 2b = -50
----------------
a = -12 ; b = -5
============
Cheers,
Stan H.

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