SOLUTION: here's my problem: tickets for the homecoming dance cost $20 for a single ticket or $35 for a couple. Ticket sales totaled $2280, and 128 people attended. How many tickets of ea

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: here's my problem: tickets for the homecoming dance cost $20 for a single ticket or $35 for a couple. Ticket sales totaled $2280, and 128 people attended. How many tickets of ea      Log On

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Question 13784: here's my problem: tickets for the homecoming dance cost $20 for a single ticket or $35 for a couple. Ticket sales totaled $2280, and 128 people attended. How many tickets of each type were sold?
Here's what I've done so far:
x+y=128 where x=# of single tickets and y=# of couple tickets
20x+35y=2280 adding value to x and y equalling total dollars
have I set up the problem correctly? I wasn't sure about the 128 in the first equation
Answer by glabow(165) About Me  (Show Source):
You can put this solution on YOUR website!
No, you have a simple error. If y is the number of tickets sold for couples, then 2y persons attend for those tickets. So, x + 2y = 128. Your equation for the dollar amount of x and y ticket sales is correct.
Solve x + 2y = 128 and 20x + 35y = 2280.
[I got x=16 and y=56]