SOLUTION: one number is 6 less than a second number, twice the second number is 39 more than 5 times the second number. find the two numbers

Question 131147: one number is 6 less than a second number, twice the second number is 39 more than 5 times the second number. find the two numbers
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
one number is 6 less than a second number, twice the second number is 39 more than 5 times the second (YOU MUST MEAN FIRST NUMBER?????) number. find the two numbers
Let x=the second number
Then x-6=the first number
Now we are told that:
2x=5(x-6)+39 get rid of parens
2x=5x-30+39 subtract 5x from both sides
2x-5x=5x-5x-30+39 collect like terms
-3x=9 divide both sides by -3
x=-3---------------------second number
x-6=-3-6=-9----------------------first number
CK
2*(-3)=5*(-9)+39
-6=-45+39
-6=-6

Hope this helps---ptaylor
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