You can
put this solution on YOUR website!x+y=3 or x=3-y
y+z=4 or y=4-z
x+z=5 or x=5-z
setting the x equations equal we get:
3-y=5-z
-y=5-3-z
y=-2+z
now set the y equations equal.
4-z=-2+z
-z-z=-2-4
-2z=-6
z=-6/-2
z=3 answer for the pumpkin.
y=-2+4
y=2 answer for the cauliflower.
x=3-2
x=1 answer for the cabbage.
You can
put this solution on YOUR website!"A cabbage and a cauliflower cost $3 in total,
a cauliflower and a pumpkin cost $4 in total
and a pumpkin and a cabbage cost $5 in total.
Find the total cost of one of each vegetable."
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This is one way to work the problem; I'm sure there are others.
Let the cauliflower cost be "a"
Let the pumpkin cost be "b"
Let the cabbage cost be "c"
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Three equations
a + 0b + c = 3
a + b + 0c = 4
0a + b + c = 5
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Subtract the 1st equation from the 2nd to get:
a + 0b + c = 3
0 + b - c = 1
0 + b + c = 5
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Subtract the 2nd equation from the 3rd to get:
a + 0b + c = 3
0 + b - c = 1
0 + 0 + 2c = 4
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Now:
1st: solve for c and get c = 2 (# of cabbages is 2)
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2nd: substitute into the 2nd equation to get:
b-2 = 1
b = 3 (# of pumpkins is 3)
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3rd: substitute into the 1st equation to get:
a + 0 + 2 = 3
a = 1 (# of cauliflower is 1)
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Good wishes on your studies.
Cheers,
Stan H.
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