SOLUTION: solve. Donna is late for a sales meeting after traveling from one town to another at a speed of 32 mph. If she had tarveled 4 mph faster, she could have made the trip in 1/2 hr le

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: solve. Donna is late for a sales meeting after traveling from one town to another at a speed of 32 mph. If she had tarveled 4 mph faster, she could have made the trip in 1/2 hr le      Log On

Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo .
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 129616This question is from textbook
: solve.
Donna is late for a sales meeting after traveling from one town to another at a speed of 32 mph. If she had tarveled 4 mph faster, she could have made the trip in 1/2 hr less time. How far apart are the towns?This question is from textbook

Answer by josmiceli(6793) About Me  (Show Source):
You can put this solution on YOUR website!
Let d= the distance apart
Let t= her actual time
d+=+32t
d+=+36%28t+-+.5%29
32t+=+36%28t+-+.5%29
32t+=+36t+-+18
4t+=+18
t+=+4.5
d+=+32%2At
d+=+32%2A4.5
d+=+144mi
The towns are 144 mi apart
check answer:
d+=+32t
d+=+36%28t+-+.5%29
144+=+32t
t+=+4.5
144+=+36t+-+18
36t+=+162
t+=+4.5
OK