SOLUTION: Leo held a garage sale. He priced all the items at a dime or a quarter. His sales totaled less than $5. Write a linear inequality for this situation What is the maximum possibl

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Leo held a garage sale. He priced all the items at a dime or a quarter. His sales totaled less than $5. Write a linear inequality for this situation What is the maximum possibl      Log On

Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo .
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

   

Question 126836This question is from textbook
: Leo held a garage sale. He priced all the items at a dime or a quarter. His sales totaled less than $5.
Write a linear inequality for this situation
What is the maximum possible number of items that could have been sold for a dime?This question is from textbook

Answer by solver91311(12126) About Me  (Show Source):
You can put this solution on YOUR website!
$5.00 is 500 cents, 10d is the amount in cents received from selling d items for a dime, and 25q is the amount in cents received from selling q items for a quarter.

10d+%2B+25q+%3C+500

This could also be expressed as 0.10d+%2B+0.25q=5.00, but I happen to think decimal coefficients are messy and best avoided if possible. Then again, maybe I'm related to Monk.

The maximum number of items that could have been sold for a dime is when zero items sold for a quarter, so the inequality reduces to:

10d+%3C+500

Dividing by 10:
d+%3C+50

Since fractional parts of a dime are not allowed in this situation, the most items that could have been sold for a dime was 49, one less than 50.