SOLUTION: A 36 foot pipe is divided into three peices. One peice is twice as long as the shortest peice and the third peice is 1 foot longer than four times the shortest peice. Find the leng
Algebra.Com
Question 125448: A 36 foot pipe is divided into three peices. One peice is twice as long as the shortest peice and the third peice is 1 foot longer than four times the shortest peice. Find the length of the shortest peice.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
LET X BE THE SHORTEST PIECE.
2X IS THE NEXT PIECE.
4X+1 IS THE LAST PIECE.
X+2X+4X+1=36
7X=36-1
7X=35
X=35/7
X=5 FEET LONG IS THE LENGTH OF THE SHORTEST PIECE.
RELATED QUESTIONS
A 60 ft. pipe is divided into three peices. One peice is twice a long as the shortest... (answered by checkley71,josmiceli)
A 16inch board is to be cut into 3 peices so that the second peice is twice as long as... (answered by richard1234)
A 25 inch rope is cut into 3 peices such that the middle sized peice is 1 inch longer... (answered by tonyna22)
the problem is: a 45ft rope is cut into 3 peices. the 2nd peice must be twice as long as (answered by Paul)
a rope measures 168 and is cut in three peices and the first peice is one-half bigger... (answered by mananth)
A 36 inch board is to be cut into three pieces so that the second piece is twice as long... (answered by stanbon)
im not quit sure what cat. this question would go under so i tried to find the closes... (answered by LilSkittleMd)
A 36-foot pipe is divided into three pieces. One piece is twice as long the shortest... (answered by josmiceli)
A 45-foot rope is to be cut into three pieces. The second piece must be twice as long as... (answered by jim_thompson5910,Electrified_Levi)