SOLUTION: A 60 ft. pipe is divided into three peices. One peice is twice a long as the shortest peice, and the third peice is 4 feet less than five times the shortest peice. Find the length

Question 125230: A 60 ft. pipe is divided into three peices. One peice is twice a long as the shortest peice, and the third peice is 4 feet less than five times the shortest peice. Find the length of the shortest peice.
Found 2 solutions by checkley71, josmiceli:
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
LET X BE THE SHORTEST PIECE.
2X IS THE NEXT PIECE.
5X-4 IS THE LONGEST PIECE.
X+2X+5X-4=60
8X=60+4
8X=64
X=64/8
X=8 FEET IS THE LENGTH OF THE SHORTEST PIECE.

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = the shortest piece
Another piece is
The 3rd piece is

ft
check

OK
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