SOLUTION: there are 429 people at a play. admission was $1.50 for adults and $0.75 for children the receipts totaled $371.25. How many adults and how many children attended the play?
Question 1203460: there are 429 people at a play. admission was $1.50 for adults and $0.75 for children the receipts totaled $371.25. How many adults and how many children attended the play? Found 3 solutions by math_tutor2020, ikleyn, greenestamps:Answer by math_tutor2020(3817) (Show Source):
You can put this solution on YOUR website!
x = number of adults
429-x = number of children
1.50x = revenue from adults
0.75(429-x) = revenue from children
1.50x+0.75(429-x) = total revenue = 371.25
You can put this solution on YOUR website! .
there are 429 people at a play.
admission was $1.50 for adults and $0.75 for children
the receipts totaled $371.25.
How many adults and how many children attended the play?
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x adults; (429-x) children.
Write the total money equation
1.50x + 0.75*(429-x) = 371.25.
Simplify and find x
1.50x + 0.75*429 - 0.75x = 371.25
1.50x - 0.75x = 371.25 - 0.75*429
0.75x = 49.50
x = 49.50/0.75 = 66.
ANSWER. 66 adults and 429-66 = 363 children.
CHECK. 1.50*66 + 0.75*363 = 371.25 dollars, total money. ! correct !
The solutions from the other tutors are good formal algebraic solutions.
If a formal algebraic solution is not required, here is an informal solution, using the fact that the cost of an adult ticket is exactly twice the cost of a child ticket.
Divide the total receipts by the cost of a child ticket:
The total receipts are enough to buy 495 child tickets.
But only 429 tickets were sold.
Since the cost of an adult ticket is twice the cost of a child ticket, the number of adults was 495-429 = 66.
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