smallest c largest c+100 third angle (1/3)(c+100) SUM 180
RESULTS smallest 20 largest 120 the third 40
In a triangle, the largest angle is 100° greater than the smallest angle. The largest angle is 3 times as large as the third angle. Find the measure of each angle. Let the measure of the MIDDLE angle be M Then measure of largest angle = 3M And, measure of smallest angle = 3M - 100 As all interior angles of a triangle sum to 180, we get: M + 3M + 3M - 100 = 180 7M = 180 + 100 Find M, the measure of the middle angle, then substitute that value to find the largest and smallest angles. FINITO!!