SOLUTION: A theater group made appearances in two cities. The hotel charge before tax in the second city was $1000 higher than in the first. The tax in the first city was 8.5%, and the tax i

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Question 1202076: A theater group made appearances in two cities. The hotel charge before tax in the second city was $1000 higher than in the first. The tax in the first city was 8.5%, and the tax in the second city was 10%. The total hotel tax paid for the two cities was $1,025. How much was the hotel charge in each city before tax?
First city- (answer)
Second city- (answer)
Found 2 solutions by mananth, josgarithmetic:
Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!
A theater group made appearances in two cities.
Let hotel charge in first city be x
The hotel charge before tax in the second city was $1000 higher than in the first.
= x+1000
The tax in the first city was 8.5%,
Total tax in first city =8.5%x
and the tax in the second city was 10%.
Total tax in the second city = (x+1000)*10%

The total hotel tax paid for the two cities was $1,025
8.5%x +(x+1000)*10% = 1025
0.085x +0.1x =1025-100
x= 5000.00 charges in first city
5000+1000=6000 charges in second city
check
5000*8.5% +6000*10%=1025



Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
CITY          HOTEL Charge     tax rate      taxes
  1                 x              8.5%      0.085x
  2                 x+1000         10       0.10(x+1000)
TOTAL                                        1025

Sum of taxes for the two combined hotels, in all a single variable, .
Solve for x, the hotel charge for in the first city:




---------hotel for first city

Hotel charge in second city:

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