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Miguel the trainer has two solo workout plans that he offers his clients: Plan A and Plan B.
Each client does either one or the other (not both).
On Monday there were 4 clients who did Plan A and 8 who did Plan B.
On Tuesday there were 2 clients who did Plan A and 3 who did Plan B.
Miguel trained his Monday clients for a total of 9 hours and his Tuesday clients for a total of 4 hours.
How long does each of the workout plans last?
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Let x = hours for plan A and y = hours for plane B.
Write equations as you read the problem
4x + 8y = 9 (1) (total hours on Monday)
2x + 3y = 4 (2) (total hours on Thursday)
To solve this system, multiply equation (2) by 2 (both sides).
Keep equation (1) as is. You will get
4x + 8y = 9 (3)
4x + 6y = 8 (4)
Now subtract equation (4) from equation (3), The terms with "4x" will cancel each other,
and you will get
8y - 6y = 9 - 8
2y = 1
y = 1/2 = 0.5.
Then from equation (2)
2x + 3*0.5 = 4,
2x + 1.5 = 4
2x = 4 - 1.5 = 2.5
x = 2.5/2 = 1.25.
ANSWER. Plan A is 1.25 hours per client (same as 1 hour and 15 minutes).
Plan B is 0.5 hours per client (same as 30 minutes).
Solved.
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On the way, you learned on how the Elimination method works,
when you solve systems of two equations in two unknowns.
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Notice that the way on how tutor @Theo introduces his unknown variables may perplex/confuse you.
Surely, x and y in his post are not the numbers of clients;
they are the hours per a client for plan A and plane B, respectively.
Precisely as they are introduced in my solution.