SOLUTION: A school is selling tickets to a talent show. On the first day of sales they sold 1 adult ticket and 6 student tickets for a total of $60. On the last day of sales, they sold 6 adu

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Question 1199504: A school is selling tickets to a talent show. On the first day of sales they sold 1 adult ticket and 6 student tickets for a total of $60. On the last day of sales, they sold 6 adult tickets and 15 student tickets for a total of $192. What was the price of the adult ticket?
Found 2 solutions by greenestamps, josgarithmetic:
Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


Informally, using logical reasoning and mental arithmetic....

Since 1 adult ticket and 6 student tickets cost $60, 6 adult tickets and 36 student tickets would cost $360.
Comparing that to the $192 cost of 6 adult tickets and 15 student tickets, we see that the 36-15=21 additional student tickets cost an additional $360-$192 = $168; so the cost of each student ticket is $168/21 = $8.
So on the first day the 6 student tickets cost 6($8) = $48, which means the 1 adult ticket cost $60-$48 = $12.

ANSWER: The price of an adult ticket was $12.

The exact same thing, using formal algebra....
x+6y = 60       given
6x+36y = 360    multiply by 6
6x+15y = 192    given
21y = 168       the difference between the two equations
y = 8           solve for y
x+6(8) = 60     solve for x
x+48 = 60
x = 12
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Price of one adult ticket, y.
Price of student ticket, x.




Questions asks for just the value of y. Try to eliminate x.

, this form of the system does not help.


Back to the original system
5*E1 and 2*E2.



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