SOLUTION: A piece of pipe is 40 in. long. It is cut into three pieces. The longest piece is 3 times as long as the middle-sized piece, and the shortest piece is 23 in. shorter than the long

Question 1194530: A piece of pipe is 40 in. long. It is cut into three pieces. The longest piece is 3 times as long as the middle-sized piece, and the shortest piece is 23 in. shorter than the longest piece. Find the lengths of the three pieces of pipe.

Found 3 solutions by Alan3354, MathTherapy, josgarithmetic:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
A piece of pipe is 40 in. long. It is cut into three pieces. The longest piece is 3 times as long as the middle-sized piece, and the shortest piece is 23 in. shorter than the longest piece. Find the lengths of the three pieces of pipe.
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L = longest piece, etc
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L = 3M ---> M = L/3
S = L - 23
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L + M + S = 40
L + L/3 + (L-23) = 40
2L + L/3 = 63
6L + L = 189
L = 27
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M = 9
S = 4
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
A piece of pipe is 40 in. long. It is cut into three pieces. The longest piece is 3 times as long as the middle-sized piece, and the shortest piece is 23 in. shorter than the longest piece. Find the lengths of the three pieces of pipe.

Let middle piece's length be M
Then longest's and shortest's lengths are: 3M and 3M - 23, respectively
We then get: M + 3M + 3M - 23 = 40
7M = 63
Middle piece's length, or
You should now be able to find the length of the other 2 pieces.
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!

NUMBER LONG x+23 MIDDLE (1/3)(x+23) SHORT x Sum 40

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