SOLUTION: consider two pain relieving drugs compared two independent samples of 1000 individuals each. suppose 750 of these individuals receiving drugs one and 800 of those receiving drug tw
Algebra.Com
Question 1192440: consider two pain relieving drugs compared two independent samples of 1000 individuals each. suppose 750 of these individuals receiving drugs one and 800 of those receiving drug two construct 90% confidence interval for the percentage of 2 pain receiving pills?
Answer by CPhill(1959) (Show Source): You can put this solution on YOUR website!
**1. Calculate the Sample Proportions**
* **Drug 1:**
* Sample proportion (p1) = 750 / 1000 = 0.75
* **Drug 2:**
* Sample proportion (p2) = 800 / 1000 = 0.80
**2. Calculate the Standard Error**
* **Pooled Proportion (p̂):**
* p̂ = (Number of successes in both samples) / (Total sample size)
* p̂ = (750 + 800) / (1000 + 1000) = 1550 / 2000 = 0.775
* **Standard Error (SE):**
* SE = √[p̂ * (1 - p̂) * (1/n1 + 1/n2)]
* SE = √[0.775 * (1 - 0.775) * (1/1000 + 1/1000)]
* SE = √[0.775 * 0.225 * (2/1000)]
* SE ≈ 0.0186
**3. Determine the Z-score for 90% Confidence Level**
* For a 90% confidence interval, the Z-score is 1.645.
**4. Calculate the Margin of Error**
* Margin of Error (ME) = Z-score * SE
* ME = 1.645 * 0.0186
* ME ≈ 0.0306
**5. Construct the Confidence Intervals**
* **Drug 1:**
* Lower limit: p1 - ME = 0.75 - 0.0306 = 0.7194
* Upper limit: p1 + ME = 0.75 + 0.0306 = 0.7806
* 90% CI for Drug 1: (0.7194, 0.7806)
* **Drug 2:**
* Lower limit: p2 - ME = 0.80 - 0.0306 = 0.7694
* Upper limit: p2 + ME = 0.80 + 0.0306 = 0.8306
* 90% CI for Drug 2: (0.7694, 0.8306)
**Interpretation:**
* We are 90% confident that the true proportion of individuals who experience pain relief with Drug 1 lies between 71.94% and 78.06%.
* We are 90% confident that the true proportion of individuals who experience pain relief with Drug 2 lies between 76.94% and 83.06%.
**Note:**
* These confidence intervals provide a range of plausible values for the true population proportions.
* The intervals do not overlap, suggesting that there might be a statistically significant difference in the effectiveness of the two drugs. However, further statistical analysis (such as a hypothesis test) would be needed to confirm this.
**Disclaimer:**
* This analysis provides a basic framework for constructing confidence intervals.
* In real-world scenarios, more sophisticated statistical methods might be necessary, especially when dealing with medical data.
* This information should not be considered medical advice.
RELATED QUESTIONS
consider two pain relieving drugs compared two independent samples of 1000 individuals... (answered by CPhill)
3. When is it appropriate to use the paired difference t-test?
A) Four samples are... (answered by stanbon)
Suppose an x distribution has mean μ = 3. Consider two corresponding
x... (answered by Boreal)
The manager of Ardmore Pharmacy knows that 25% of the customers entering the store buy... (answered by mathmate)
In a two-sample test of means for independent samples, the equal sign always appears... (answered by stanbon)
The following are measurements of the heat-producing capacity (in millions of calories... (answered by Boreal)
The following are measurements of the heat-producing capacity (in millions of calories... (answered by ikleyn)
Using two independent samples, two population means are compared to determine if a... (answered by stanbon)
If the two samples are not independent, their population means can still be compared... (answered by stanbon)