SOLUTION: If n=5 and p=0.2 of binomial distribution.find P(X greater than 3)=?

Question 1192058: If n=5 and p=0.2 of binomial distribution.find P(X greater than 3)=?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
n = 5 and p = .2
q = 1 - p = .8
x = 0 to 5
formula is:
p(x) = p^x * q^(n-x) * c(n,x)
when p = .2 and q = .8 and n = 5, formula becomes:
p(x) = .2^x * .8^(n-x) * c(5,x)
p(x>3) would be equal to p(4) + p(5)
p(4) = .2^4 * .8^1 * c(5,4) = .0064
p(5) = .2^5 * .8^0 * c(5,5) = .00032
add them up and you get:
p(x>3) = .00672
that's your answer.

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