We have three consonants M, G and C as three separate items and we have the block of two vowels AI as the fourth item. There are 4! = 1*2*3*4 = 24 possible permutations of these four items, and there are 2 permutations of the vowels A and I inside the block. In all, it gives 2*4! = 2*24 = 48 possible different permutations/arrangements. ANSWER