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There are 6 boys who enter a boat with 8 seats, 4 on each side.
In how many ways can they sit anywhere on the boat?
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Let us assume that all seats are numbered from 1 to 8.
1st boy can sit any of 8 seats.
2nd boy can sit any of remaining 7 seats.
3rd boy can sit . . . and so on . . .
Finally, there are 8*7*6*5*4*3 = 20160 different sitting permutations (arrangements). ANSWER
Solved.
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This problem is on PERMUTATIONS.
On Permutations, see introductory lessons
- Introduction to Permutations
- PROOF of the formula on the number of Permutations
- Simple and simplest problems on permutations
- Special type permutations problems
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.