SOLUTION: The cost of admission to the Christmas Carnival was $50 for a group of 9 children and 2 adults. The admission was $60 for another group of 10 children and 4 adults. What was the a

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Question 1188683: The cost of admission to the Christmas Carnival was $50 for a group of 9 children and 2 adults. The admission was $60 for another group of 10 children and 4 adults. What was the admission price for each child? What was the admission price for each adult?
Found 2 solutions by Shin123, Boreal:
Answer by Shin123(626)   (Show Source): You can put this solution on YOUR website!
Letting x be the cost of admission for 1 child, and y for 1 adult, we have
Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
We'll use substitution. After moving 2*y to the right, we get:
, or . Substitute that
into another equation:
and simplify: So, we know that y=2.5. Since , x=5.

Answer: .

Therefore, the admission for a child cost $5, and an adult $2.50.

Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
9C+2A=50; C=children, A=adult
10C+4A=60
multiply the top by -2 and add
-18C-4A=-100
10C+4A=60
-8C=-40
C=$5 for children
substitute into first
45+2A=-0
A=$2.50
-
check using second
10(5)+4(2.50)=60, and that is true.

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