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Admission prices in the bunawan variety shows where 20 pesos and fifty pesos
the total cash in one of the ticket booth was 9550 tickets were sold to 320 people
how many of each kind of tickets were sold
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It looks like a standard ticket problem.
You can start from the standard form equations
x + y = 320 (1)
20x + 50y = 9550 (2)
where x is the number of the 20-pesos tickets; y is the number of the 50-pesos tickets.
Then you express x = 320-y from the first equation and substitute it into the second equation
20(320-y) + 50y = 9550 pesos. (3)
Alternatively, you can start directly from equation (3) - it is up to you.
From equation (3),
y = = 105.
So, there are 105 50-peso tickets, and the rest (320-105) = 215 tickets are for 20 pesos. ANSWER
CHECK. 50*105 + 20*215 = 9550 pesos, the total money. ! Correct !
Solved.
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It is a standard and typical tickets problem.
There are different methods of solving such problems.
In this site, there are lessons
- Using systems of equations to solve problems on tickets
- Three methods for solving standard (typical) problems on tickets
explaining and showing all basic methods of solving such problems.
From these lessons, learn on how to solve such problems once and for all.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Systems of two linear equations in two unknowns".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.