SOLUTION: "A truck that hauls water is capable of carrying a maximum of 1600 lb. Water weighs 8.3454 lb/gal, and the plastic tank on the truck that holds water weighs 90 lb. Assume the

Question 1186735: "A truck that hauls water is capable of carrying a maximum of 1600 lb. Water weighs

8.3454 lb/gal, and the plastic tank on the truck that holds water weighs 90 lb. Assume the truck can carry a maximum of gallons of water. Write an inequality to model this scenario. There is no need to solve it."
Answer by ikleyn(52776) (Show Source): You can put this solution on YOUR website!
.
"A truck that hauls water is capable of carrying a maximum of 1600 lb. Water weighs
8.3454 lb/gal, and the plastic tank on the truck that holds water weighs 90 lb.
Assume the truck can carry a maximum of gallons of water.
Write an inequality to model this scenario. There is no need to solve it."
~~~~~~~~~~~~~~~

The requested inequality is


    8.3454*G + 90  <= 1600  lb,


where G is the number of GALLONS.

Solved, explained and completed.

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