SOLUTION: Two cyclists start at the same point and travel in opposite directions. One cyclist travels 5 mi/h faster than the other. If the two cyclists are 155 miles apart after 5 hours, wha

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Question 1186103: Two cyclists start at the same point and travel in opposite directions. One cyclist travels 5 mi/h faster than the other. If the two cyclists are 155 miles apart after 5 hours, what is the rate of each cyclist?
Found 2 solutions by JBnovelwriter, MathTherapy:
Answer by JBnovelwriter(34)   (Show Source): You can put this solution on YOUR website!









13m/hr
18m/hr
Answer by MathTherapy(10551)   (Show Source): You can put this solution on YOUR website!

Two cyclists start at the same point and travel in opposite directions. One cyclist travels 5 mi/h faster than the other. If the two cyclists are 155 miles apart after 5 hours, what is the rate of each cyclist?
Let rate of slower cyclist be S

Then rate of faster cyclist = S + 5

We then get the following DISTANCE equation: 5S + 5(S + 5) = 155

S + S + 5 = 31 ------ Factoring out GCF, 5/Dividing by 5

2S = 26

Speed of slower cyclist, or 

You should now be able to find the faster cyclist's rate/speed. 

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