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Let x = amount (the mass in grams) of the 90% cocoa.
Then the mass of the 80% cocoa is (300-x) grams.
After that, write the standard equation of conservation mass (the pure cocoa)
in the mixture before and after the mixing
0.9x + 0.8(300-x) = 0.86*300.
From this equation
x = = 180.
ANSWER. 180 grams of the 90% cocoa and the rest, (300-180) = 120 grams of the 80% cocoa.
CHECK. I will check the concentration = 0.86 = 86%. ! Precisely correct !
Solved.
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In this site, there is entire bunch of lessons covering various types of mixture problems.
Of them the most closest to your problem are
- Word problems on mixtures for dry substances like coffee beans, nuts, cashew and peanuts
- Word problems on mixtures for dry substances like candies, dried fruits
- Word problems on mixtures for dry substances like soil and sand
Read them and become an expert in solution the mixture word problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Mixture problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.