SOLUTION: Twice the first number plus 3 times the second number is 87. Three times the first minus
twice the second is -6. Find the numbers.
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Question 1175725: Twice the first number plus 3 times the second number is 87. Three times the first minus
twice the second is -6. Find the numbers.
Found 2 solutions by Solver92311, Alan3354:
Answer by Solver92311(821) (Show Source): You can put this solution on YOUR website!
Solve the 2X2 System for 
and 
by any convenient means (Substitution, Elimination, Cramer's Rule, etc.). I would recommend Cramer's Rule as it works out quite tidily (no really ugly arithmetic)
John
My calculator said it, I believe it, that settles it
From
I > Ø
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Twice the first number plus 3 times the second number is 87.
---
2a + 3b = 87 Eqn 1
================
Three times the first minus twice the second is -6. Find the numbers.
---
3a - 2b = -6 Eqn 2
================================
4a + 6b = 174 Eqn 1 times 2
9a - 6b = -18 Eqn 2 times 3
----------------------------------- Add
13a = 156
a = 12
etc
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