SOLUTION: The length of a new rectangularqua playing field is 6 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 532 yards, what are its dimensi
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Question 1174476: The length of a new rectangularqua playing field is 6 yards longer than quadruple the width. If the perimeter of the rectangular playing field is 532 yards, what are its dimensions?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The length of a new rectangular playing field is 6 yards longer than quadruple the width.
w = the width
L = 4w + 6, the length
If the perimeter of the rectangular playing field is 532 yards, what are its dimensions?
2(4w+6) + 2w = 532
simplify, divide by 2
4w + 6 + w = 266
4w + w = 266 - 6
5w = 260
w = 260/5
w = 52 yds is the width
then
4(52) + 6 = 214 yds is the length
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Check this by finding the perimeter with these values
2(214) = 428
2(52) = 104
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perimeter:532
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