SOLUTION: Scott and Laura have both invested some money. Scott invested $2,500 more than Laura and at a 2% higher interest rate. If Scott received $900 annual interest and Laura received $40

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Question 1174374: Scott and Laura have both invested some money. Scott invested $2,500 more than Laura and at a 2% higher interest rate. If Scott received $900 annual interest and Laura received $400, how much did Scott invest? (There are two possibilities for how much Scott invested.
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13216)   (Show Source): You can put this solution on YOUR website!


Let x be the amount Laura invested
Then x+2500 is the amount Scott invested

Let y be Laura's interest rate (as a decimal)
Then Scott's interest rate is y+.02

Laura's interest was $400:
(1)

Scott's interest was $900:


Solve (1) for y and substitute in (2):


You can foil out the expression on the left and convert the resulting equation to a quadratic and try to solve the problem by factoring. However, the coefficients of the quadratic will make factoring very difficult.

So you might as well graph the expressions on the two sides of the equation on a graphing calculator and find where they intersect.

I leave it to you to do that; you won't gain any knowledge or problem solving experience if I do it for you.

You will indeed find there are two possible answers (both of them "nice" numbers) for the amount that Scott invested.


Answer by ikleyn(52918)   (Show Source): You can put this solution on YOUR website!
.
Scott and Laura have both invested some money. Scott invested $2,500 more than Laura and at a 2% higher interest rate.
If Scott received $900 annual interest and Laura received $400, how much did Scott invest?
(There are two possibilities for how much Scott invested.
~~~~~~~~~~~~~~


            This problem has very interesting,  elegant and unexpected solution.

            In addition,  it has beautiful core,  that you rarely may find in such problems.

            It is  WORTH  to learn.     It is  WORTH  to teach.     Watch my steps attentively.


Let x be the the annual interest of the Scott's investment (as decimal).

Then Laura's annual interest is (x-0.02).


    +------------------------------------------------------------------------+
    |  This variable x is the only unknown I will use in my solution.        |
    +------------------------------------------------------------------------+



Then the  Scott's principal investment is  {{900/x}}}  dollars,

while the Laura's principal investment is    dollars.



According to the condition, the difference of their principals is 2500;

it gives you the core equation


     -  = 2500.      (1)


At this point, the setup is just completed, and now I start solving this equation.



First, divide by 100 both sides

     -  = 25.


Next, multiply both sides by x*(x-0.02) and simplify, step by step

    9*(x-0.02) - 4x = 25x*(x-0.02)

    9x - 0.18  - 4x = 25x^2 - 0.5x

       5x -0.18     = 25x^2 - 0.5x

       25x^2 - 5.5x + 0.18 = 0

     =  =  = .


So, there are two roots:   =  =  = 0.18,

                  and      =  =  = 0.04.


Both the roots satisfy the basic equation (1):

    x= 0.18:    -  = 5000 - 2500 = 2500 dollars.      ! correct !

and

    x= 0.14:    -  = 22500 - 20000 = 2500 dollars.    ! correct !


Thus for Scott's investment, we have two possible answers: a)   = 5000 dollars  and/or  b)  = 22500 dollars.

Solved.

Honestly, it is for the first time in my life I see so beatiful solution to this class of problems.

-------------

When you complete reading it, do not forget to post your "THANKS" to me for my teaching.




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