Hi, Find the area of a triangle bounded by the y-axis, the line f(x) = 7− (2)/(7)x y = -(2/7)x + 7 and the line perpendicular to f(x) that passes through the origin... y = (7/2)x ---------- 7 − (2/7)x = (7/2)x 7 = (4 + 49)/14)x = (x)53/14 (14/53)7 = x = 1.849 and y = 6.47------------- D = P(1.849, 6.47) & P(0,0) and P(1.849, 6.47) & P(0,7) Area = (1/2)bh = Will leave it to You to finish up. Important You are comfortable with Your calculator. Wish You the Best in your Studies.
The two lines are y =+ 7 y = . Their intersection is = . Multiply both sides by 14 to get -4x + 98 = 49x 98 = 49x + 4x = 53x x = . You may consider the segment [0,7] along the y-axis as the base of our right-angled triangle. Thus the base has the length of 7 units, while the altitude of the triangle, drawn to this base is units long. Hence, the area of the triangle is = = 6.472 square units (rounded). ANSWER