SOLUTION: H= -5t^2+20t models the height of a ball that is kicked into the air, where H is the ball's height in meters and t is time in seconds after being kicked.
a) How long is the ball
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Question 1169625: H= -5t^2+20t models the height of a ball that is kicked into the air, where H is the ball's height in meters and t is time in seconds after being kicked.
a) How long is the ball in the air for?
b) When will the ball reach its maximum height?
c) What is the maximum height reached by the ball?
d) At what time(s) will the ball be 15 meters in the air?
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
a) How long is the ball in the air for?
-> t is time in seconds, so set H=0 and solve for t
if ->
or
if ->-> your solution is: the ball is in the air for seconds
b) When will the ball reach its maximum height?
trajectory is a parabola and maximum is vertex
write in vertex form, complete square
...first factor out
... complete square
...
vertex is at (, )=> the ball reach its maximum in seconds
c) What is the maximum height reached by the ball?
the maximum height reached by the ball is
d) At what time(s) will the ball be meters in the air?
....solve for
...will be zero if
....factor
=> ,
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