SOLUTION: The owner of a movie theater needs to bring in $1600 revenue at each screening in order to stay in business. He sells adults' tickets for $11 each and children's tickets at $9 each

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Question 1164330: The owner of a movie theater needs to bring in $1600 revenue at each screening in order to stay in business. He sells adults' tickets for $11 each and children's tickets at $9 each.
a. How much revenue does he earn from selling
x
adults' tickets?
b. How much revenue does he earn from selling
y
children's tickets?
c. Write an equation in
x
and
y
for the number of tickets he must sell at each screening.
Found 2 solutions by jim_thompson5910, ikleyn:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

Part A) They earn 11x dollars in revenue from all the adults
We can think of it like this
1 adult = 11 dollars
x adults = 11x dollars
after multiplying both sides by x

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Part B) This is similar to part A. One child ticket costs $9 each, so selling y of them leads to 9y dollars.

---------------------------------------------------------

Part C) We earn 11x dollars from all the adults and 9y dollars from all the children. The total revenue is 11x+9y dollars.
The owner wants to bring in $1600, so we set 11x+9y equal to 1600 to get the equation 11x+9y = 1600
Answer by ikleyn(52812)   (Show Source): You can put this solution on YOUR website!
.

To be adequate to real life,  the problem must be formulated  DIFFERENTLY. 

    The owner of a movie theater needs to bring  at least $1600 revenue 
    at each screening in order to stay in business. He sells adults' tickets 
    for $11 each and children's tickets at $9 each.


    a.  How much revenue does he earn from selling x adults' tickets?

    b.  How much revenue does he earn from selling y children's tickets?

    c.  Write an  inequality in x and y for the number of tickets he must sell at each screening.


            Then the answer for  (c)  is  THIS  

                11x + 9y >= 1600 dollars. 

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