Let slower airplane's speed, be S

Then faster airplane's speed = S + 97

We then get the following DISTANCE equation: 8S + 8(S + 97) = 12,344

8S + 8S + 8(97) = 12,344 

16S = 12,344 - 8(97)

Speed of slower airplane, or 

Now, add 97 to the slower speed to get the faster! 

Answer by ikleyn(52792)   (Show Source): You can put this solution on YOUR website!
 .


Let "r" be the rate of the slower plane, in miles per hour.

Then the rate of the faster plane is (r+97) mph.


The total distance equation is


    12344 = 8r + 8*(r+97)


Simplify and solve


    r + (r+97) = 12344/8 = 1543

    2r                   = 1543-97 = 1446

     r                             = 1446/2 = 723.


ANSWER.  The rates of the planes are  723 mph  and  723+97 = 820 mph.




Solved.





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