SOLUTION: April shoots an arrow upward into the air at a speed of 64 feet per second from a platform that is 11 feet high. The height of the arrow is given by the function h(t)= -16t^2 + 64t
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Question 1158962: April shoots an arrow upward into the air at a speed of 64 feet per second from a platform that is 11 feet high. The height of the arrow is given by the function h(t)= -16t^2 + 64t +11, where t is the time is seconds. What is the maximum height of the arrow?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
h(t)= -16t^2 + 64t +11
the maximum height is at the vertex, and the x value of the vertex is at -b/2a or -64/-32 or +2 seconds.
h(2)=-64+128+11
=75 feet
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