SOLUTION: The height of a projectile launched upward at a speed of 32 feet/second from a height of 48 feet is given by the function: h(t)=-16t^2+32t+48. How long will it take the projectile

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Question 1153458: The height of a projectile launched upward at a speed of 32 feet/second from a height of 48 feet is given by the function: h(t)=-16t^2+32t+48. How long will it take the projectile to hit the ground?
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

The height of a projectile launched upward at a speed of from a feet is given by the function:
How long will it take the projectile to hit the ground?
the projectile will hit the ground when
......factor





we need only positive solution for the time


Therefore, the time is

Answer by ikleyn(52795)   (Show Source): You can put this solution on YOUR website!
.

Your basic equation is

    h(t) = -16t^2 + 32t + 48.



The projectile will hit the ground when h(t) = 0.



Thus the equation to solve is

    -16t^2 + 32t + 48 = 0.    (1)


You can simplify this equation SIGNIFICANTLY dividing both sides by -16. 

You will get an EQUIVALENT equation

    t^2 - 2t - 3 = 0.    (2)


The term "EQUIVALENT" means that it has the same roots as equation (1).


Now you can factor equation (2) easily  (and MENTALLY)

    (t-3)*(t+1) = 0.


The roots are  t= 3  and  t= -1, and only  positive root t= 3 is meaningful.


ANSWER.  The projectile will hit the ground in 3 seconds.


Solved.


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