SOLUTION: 3x+y-4z=-6 2x+3y-4z=4 x-y+2z=-4

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Question 1152439: 3x+y-4z=-6
2x+3y-4z=4
x-y+2z=-4

Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
3x+y-4z=-6
2x+3y-4z=4
x-y+ 2z=-4
------------
Multiply the 3rd eqn by 2 --> 2x - 2y + 4z = -8
----
Add that to the 1st and to the 2nd eqn.
z is eliminated.
You have 2 eqns in x & y.
--------------
3x +  y - 4z = -6
2x - 2y + 4z = -8
------------------------------ Add
5x - y = -14  ----  Eqn A
==========================
2x + 3y - 4z = 4
2x - 2y + 4z = -8
------------------------------- Add
4x + y = -4  ----   Eqn B
============================
5x - y = -14  ----  Eqn A
4x + y = -4  ----   Eqn B
-------------------------------- Add
9x = -18
x = -2
=============
4x + y = -4  ----   Eqn B
-8 + y = -4
y = 4
=====================
3x+y-4z=-6  -------- 1st eqn
-6 + 4 - 4z = -6
4z = 4
z = 1
----> (-2,4,1)

=======================================================
Mathlover used substitution.
I think that takes more work (in this case) than elimination.
-------
I would use a matrix because I have an Excel sheet that does those, but it doesn't teach anything, just gives the answers.

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

..........1
.........2
............3

start with

............3...solve for
............3a
then,
.........2..solve for

.........2a

from 2a and 3a we have

.......solve for



................2b
go to
............3a, substitute


...........3b

go to
..........1...substitute and , and solve for









go to
...........3b.....substitute
...........3b



go to
................2b...substitute




solutions:




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