SOLUTION: "The base of a triangle is x cm long and its altitude is quarter the length of its base. If the triangle has an area of 12 cm^2, from an equation in x and solve it. State the altit
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Question 1151122: "The base of a triangle is x cm long and its altitude is quarter the length of its base. If the triangle has an area of 12 cm^2, from an equation in x and solve it. State the altitude of the triangle."
The length of a parallelogram is d cm and its altitude is 3 cm shorter. The side of a square is shorter by a further 2 cm. If the sum of the areas of the parallelogram and square is 95 cm^2, prove the 2d^ - 13d -70=0. Hence find the length oh the parallelogram in centimeters.
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
The base of a triangle is cm long and its altitude is quarter= the length of its base.
then the length of its altitude is
If the triangle has an area of , from an equation in and solve it.
-> exact solution
-> approximate solution
the altitude of the triangle is:
=>=>-> exact solution
2.
The length of a parallelogram is cm and its altitude is cm shorter.
altitude is
The side of a square is shorter by a further cm=> The side of a square is
If the sum of the areas of the parallelogram and square is cm^2, prove the :
...to find use quadratic formula
-> since looking for the length oh the parallelogram, disregard negative solution
find the length oh the parallelogram is centimeters
check the areas:
length of a parallelogram is cm and its altitude is cm
The side of a square is cm, and area is
the sum of the areas of the parallelogram and square is which confirms our solution
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