.
The formula for the height is
h(t) = -16t^2 + 112t + 8.
The time to get the maximum height is t = = = = 3.5 seconds.
I refer to the formula x = for the general form quadratic function y = ax^2 + bx + c.
The maximum height you can get by substituting this value of time t= 3.5 seconds into the formula (1)
h(3.5) = -16*3.5^2 + 112*3.5 + 8.
Use your calculator.
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To see many other similar solved problems, look into the lessons
- Problem on a projectile moving vertically up and down
- Problem on an arrow shot vertically upward
- Problem on a ball thrown vertically up from the top of a tower
- Problem on a toy rocket launched vertically up from a tall platform
in this site.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook under the topic "Projectiles launched/thrown and moving vertically up and dawn".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.