SOLUTION: A sorority held a bake sale to raise money and sold brownies and chocolate chip cookies. They priced the brownies at $2 and the chocolate chip cookies at $1, raising $250 and sell

Question 1138774: A sorority held a bake sale to raise money and sold brownies and chocolate chip cookies. They priced the brownies at $2 and the chocolate chip cookies at $1, raising $250 and selling 175 items. How many brownies (b) and how many cookies (c) were sold?

Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

b = # of brownies
c = # of chocolate chip cookies

(1) the total number of items sold was 175
(2) the total cost of the items, at $2 each for the brownies and $1 each for the cookies, was $250

Solve the equations by whatever method you choose. Elimination certainly looks the easiest, since subtracting the first equation from the second immediately give you the value of b:

So 75 brownies and 100 chocolate chip cookies were sold.

You can get the answer using virtually the same calculations informally, using logical reasoning instead of formal algebra:

(1) If all 175 items were cookies, the total sales would be $175; but the actual total is $250, which is $75 more than that.
(2) Each brownie costs $1 more than each cookie.
(3) Therefore, to make the additional $75, the number of brownies that was sold has to be $75/$1 = 75.
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