SOLUTION: A father is 7 times as old as his son.2 years ago the father was 13 times as old as his son, how old are they now.
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Question 113508: A father is 7 times as old as his son.2 years ago the father was 13 times as old as his son, how old are they now.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
DAD=7X WHEN THE SON'S AGE IS X NOW.
2 YEARS AGO THEY WERE:
DAD=(7X-2) & THE SON=(X-2)
SO WE HAVE:
7X-2=13(X-2)
7X-2=13X-26
7X-13X=-26+2
-6X=-24
X=-24/-6
X=4 THE AGE OF THE SON NOW.
THUS THE DAD=7*4=28 YEARS OLD NOW.
PROOF:
7*4-2=13(4-2)
28-2=13*2
26=26
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