SOLUTION: If {{{p/q}}} is a fraction in lowest terms, must {{{p^2/q^2}}} be in lowest terms also? How about
{{{(p + a)/(q + a)}}} for some integer {{{a}}}?
Algebra.Com
Question 1132162: If is a fraction in lowest terms, must be in lowest terms also? How about
for some integer ?
Answer by greenestamps(13203) (Show Source): You can put this solution on YOUR website!
(a) Yes. If p/q is in lowest terms, then p and q have no common divisors.
In that case, p^2/q^2 = (p*p)/(q*q) will also have no common divisors.
(b) No, of course not. It is easy to find counterexamples.
5/7 is in lowest terms; (5+1)/(7+1) = 6/8 is not.
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