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I will solve the problem using the Linear Programming method.
Let X and Y be the numbers of gallons of liquid C and D, respectively.
Then the objective function is F(X,Y) = X + Y.
The constraint inequalities are
1*x + 6*Y <= 36 (1) (red dye constraint)
2*X + 1*Y <= 28 (2) (blue dye constraint)
X >= 0, Y >= 0.
The feasibility region is shown in the figure below.
It is the quadrilateral in QI, adjacent to x- and y- axes and constrained by the red and the green lines.
Plots 1X + 6Y = 36 (red) and 2X + Y = 28 (green)
The feasibility quadrilateral has the corner
P1 = (0,6) (red line y-intercept);
P2 = (12,4) (intersection point of the red and green lines); and
P3 = (14,0) (green line x-intercept).
The objective function has the values
at P1: F(X,Y) = 0 + 6 = 6;
at P2: F(X,Y) = 12 + 4 = 16; and
at P3: F(X,y) = 14 + 0 = 14.
According to the Linear programming method, it means that the point P2 gives the solution to the given linear minimax problem:
The most amount of gallons you can create of both color C and color D is 16.
It happens when 12 gallons of the liquid C and 4 gallons of the liquid D is produced.
Solved.
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If you want to see other similar minimax problems, solved by the Linear programming method, look into the lesson
- Solving minimax problems by the Linear Programming method
in this site.