SOLUTION: Mary has a hamburger stand in town. She says there is a linear relationship between the price (p) of hamburgers and the number sold (x) i.e. 𝒙=𝒂𝒑+𝒃.

Question 1123746: Mary has a hamburger stand in town. She says there is a linear relationship between the price (p) of hamburgers and the number sold (x) i.e. 𝒙=𝒂𝒑+𝒃. At N$10 she sells 1360 hamburgers per month, but only 510 when she doubles the price.
a) Find a and b
(b) How many hamburgers will be sold at N$16?
(c) What price will ensure sales of 1020 hamburgers?
(d) What is the maximum possible price?

Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

, number sold
, price

Points might be thought order pairs, (,).
The description using that form of equation gives this system:
....eq.1
.....eq.2
----------------------------------------------
a) Find and
Simplify and solve for and.
....eq.1
.....eq.2
----------------------------------------------subtract eq.1 from rq.2

substitute it in eq.1 and find
....eq.1

so, your equation is:

(b) How many hamburgers will be sold at N$?

(d) What is the maximum possible price?

find out what price will sell hamburgers

-> the maximum possible price
if you want to sell something, the maximum possible price be less than $
if we go with $, we will get

the maximum possible price of $ will result in sold

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SOLUTION: Mary has a hamburger stand in town. She says there is a linear relationship between the price (p) of hamburgers and the number sold (x) i.e. &#119961;=&#119938;&#119953;+&#119939;.

SOLUTION: Mary has a hamburger stand in town. She says there is a linear relationship between the price (p) of hamburgers and the number sold (x) i.e. 𝒙=𝒂𝒑+𝒃.