Question 1123123: Jose and Joy have $600 to share jaja has $240 more than Jose how much does each have simultaneous equation Found 2 solutions by Theo, josgarithmetic:Answer by Theo(13342) (Show Source): You can put this solution on YOUR website! x = amount that jose has.
y = amount that joy has.
x + y = 600 is your equation.
jaja has 240 more than jose.
i'll assume you meant joy.
joy has 240 more than jose.
x = y + 240 is your equation for this.
the two equations that need to be solved simultaneously are:
x + y = 600
x = y + 240
since x = y + 240 from the second equation, replace x with y + 240 in the first equation to get:
first equation is now y + 240 + y = 600
combine like terms to get 2y + 240 = 600
subtract 240 from both sides of the equation to get 2y = 360
divide both sides of the equation by 2 to get y = 180
since x = 240 more than y, then x must be equal to 180 + 240 = 420
x = 420
y = 180
x + y = 600 becomes 420 + 180 = 600 which becomes 600 = 600 which is true.
x = y + 240 becomes 420 = 180 + 240 which becomes 420 = 420 which is also true.
the solution looks good because both original equations are true.
since x = 420 the amount that joy has and y = the amount that jose has, then the solution is:
joy has 420
jose has 180
here's a reference on how to solve simultaneous equations.