SOLUTION: : If an object is projected upward with an initial velocity of 123 ft per sec, its height h after t seconds is h=-16^2+123t. Find the height of the object after 5 seconds.
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Question 1117160: : If an object is projected upward with an initial velocity of 123 ft per sec, its height h after t seconds is h=-16^2+123t. Find the height of the object after 5 seconds.
Found 2 solutions by KMST, Alan3354:
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
Your formula for height has a typo.
The height (in feet) after seconds can be calculated as
.
We can find the height after seconds,
by just plugging in for in the correct formula:
.
Five seconds after the object is launched upwards,
its height is .
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
: If an object is projected upward with an initial velocity of 123 ft per sec, its height h after t seconds is h=-16^2+123t. Find the height of the object after 5 seconds.
-------------
Sub 5 for t.
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